Как сравнить две даты, вернуть число дней
как я могу сравнить два даты возврата числа дней.
Пример: Отсутствует X дней Кубка.
посмотрите мой код.
NSDateFormatter *df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"d MMMM,yyyy"];
NSDate *date1 = [df dateFromString:@"11-05-2010"];
NSDate *date2 = [df dateFromString:@"11-06-2010"];
NSTimeInterval interval = [date2 timeIntervalSinceDate:date1];
//int days = (int)interval / 30;
//int months = (interval - (months/30)) / 30;
NSString *timeDiff = [NSString stringWithFormat:@"%dMissing%d days of the Cup",date1,date2, fabs(interval)];
label.text = timeDiff; // output (Missing X days of the Cup)
Ответы
Ответ 1
Из Пример Apple, в основном используйте NSCalendar:
NSDate * date1 = <however you initialize this>;
NSDate * date2 = <...>;
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit;
NSDateComponents *components = [gregorian components:unitFlags
fromDate:date1
toDate:date2 options:0];
NSInteger months = [components month];
NSInteger days = [components day];
Ответ 2
Вы можете использовать следующую категорию:
@interface NSDate (Additions)
-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate;
-(NSInteger)numberOfHoursUntilDay:(NSDate *)aDate;
@end
@implementation NSDate (Additions)
const NSInteger secondPerMunite = 60;
const NSInteger munitePerHour = 60;
const NSInteger hourPerDay = 24;
-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate
{
NSInteger selfTimeInterval = [aDate timeIntervalSinceDate:self];
return abs(selfTimeInterval / (secondPerMunite * munitePerHour * hourPerDay));
}
-(NSInteger)numberOfHoursUntilDay:(NSDate *)aDate
{
NSInteger selfTimeInterval = [aDate timeIntervalSinceDate:self];
return abs(selfTimeInterval / (secondPerMunite * munitePerHour));
}
@end
Ответ 3
Необходимо вызвать этот метод и установить только 2 даты, которые мы хотим рассчитать по-разному.
-(void) calculateSleepHours:(NSDate *)sleepDate :(NSDate *)wakeStr
{
if (sleepDate !=nil && wakeStr!=nil) {`enter code here`
NSDateFormatter *dateFormatter1 = [[NSDateFormatter alloc] init];
[dateFormatter1 setDateFormat:@"yyyy-MM-dd HH:mm:ssZ"];
NSDate *date1 = [ApplicationManager getInstance].sleepTime;;
NSDate *date2 = [ApplicationManager getInstance].wakeupTime;
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit|NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit;
NSDateComponents *components = [gregorian components:unitFlags
fromDate:date1
toDate:date2 options:0];
NSInteger months = [components month];
NSInteger days = [components day];
NSInteger hours = [components hour];
NSInteger minute=[components minute];
NSInteger second=[components second];
DLog(@"Month %ld day %ld hour is %ld min %ld sec %ld ",(long)months,(long)days,(long)hours,(long)minute,(long)second);
sleepHours.text=[NSString stringWithFormat:@"Hour %ld Min %ld Sec %ld",(long)hours,(long)minute,(long)second];
}
}
Ответ 4
Пробуйте эту категорию:
@interface NSDate (DateUtils)
-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate;
@end
@implementation NSDate (DateUtils)
-(NSInteger)numberOfDaysUntilDay:(NSDate *)aDate
{
NSCalendar *calendar = [[NSCalendar alloc]
initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSDateComponents *components = [calendar components:NSCalendarUnitDay
fromDate:self
toDate:aDate options:kNilOptions];
return [components day];
}
@end
Вы можете использовать эту категорию, добавив импорт:
#import "NSDate+DateUtils.h"
И назовите его из своего кода:
NSInteger days = [myDate numberOfDaysUntilDay:someOtherDate];