Десериализация XML в POJO с использованием Jackson XmlMapper
Используя аннотации Jackson XmlMapper, как бы десериализовать этот XML в pojo?
<?xml version="1.0" encoding="UTF-8"?>
<open>
<creds priv="write" type="internal">
<user>Username1</user>
<client_token>abcplaudzrbcy37c</client_token>
<client_secret>0cxDE3LE0000=</client_secret>
</creds>
<creds priv="read" type="internal">
<user>Username1</user>
<client_token>123plaudzrbcy37c</client_token>
<client_secret>0cxDE3LE1234=</client_secret>
</creds>
<creds priv="none" type="internal">
<user>Username1</user>
<client_token>000plaudzrbcy37c</client_token>
<client_secret>0cxDE3LEabcd=</client_secret>
</creds>
</open>
Я попытался использовать что-то вроде этого:
@JacksonXmlRootElement(localName = "Open")
public class OpenCredentials {
@JacksonXmlProperty(localName = "Credentials")
private Credentials[] credentials;
}
class Credentials {
@JacksonXmlProperty(isAttribute = true)
private String priv;
@JacksonXmlProperty(isAttribute = true)
private String type;
@JacksonXmlProperty(localName = "Creds")
private Creds[] creds;
}
class Creds {
@JacksonXmlText(value = true)
private String user;
@JacksonXmlText(value = true)
private String client_token;
@JacksonXmlText(value = true)
private String client_secret;
}
Когда я пытался использовать XmlMapper readValue(), я получаю следующую ошибку:
com.fasterxml.jackson.databind.JsonMappingException: Duplicate property '' for [simple type, class com.company.data.utils.api.Creds]
at com.fasterxml.jackson.databind.deser.DeserializerCache._createAndCache2(DeserializerCache.java:268)
at com.fasterxml.jackson.databind.deser.DeserializerCache._createAndCacheValueDeserializer(DeserializerCache.java:243)
Ответы
Ответ 1
Ваши классы POJO
не соответствуют вашему XML
. Структура проще, чем вы думали. Смотрите ниже пример:
@JacksonXmlRootElement(localName = "open")
class OpenCredentials {
@JacksonXmlProperty(localName = "creds")
@JacksonXmlElementWrapper(useWrapping = false)
private Credentials[] credentials;
//getters, setters, toString
}
class Credentials {
@JacksonXmlProperty(isAttribute = true)
private String priv;
@JacksonXmlProperty(isAttribute = true)
private String type;
private String user;
@JacksonXmlProperty(localName = "client_token")
private String clientToken;
@JacksonXmlProperty(localName = "client_secret")
private String clientSecret;
//getters, setters, toString
}
Простое использование:
XmlMapper mapper = new XmlMapper();
OpenCredentials openCredentials = mapper.readValue(XML, OpenCredentials.class);
System.out.println(openCredentials);
Над печатью программы (для вашего XML
):
OpenCredentials{credentials=[Credentials{priv='write', type='internal', user='Username1', client_token='abcplaudzrbcy37c', client_secret='0cxDE3LE0000='}, Credentials{priv='read', type='internal', user='Username1', client_token='123plaudzrbcy37c', client_secret='0cxDE3LE1234='}, Credentials{priv='none', type='internal', user='Username1', client_token='000plaudzrbcy37c', client_secret='0cxDE3LEabcd='}]}
Смотрите также:
- jackson-dataformat-xml.
- Домашняя страница: Джексон XML-база данных Wiki.
Ответ 2
import com.fasterxml.jackson.dataformat.xml.XmlMapper;
import java.io.IOException;
import java.io.StringReader;
import Parse_XML_to_Java_Objects.OpenCredentials;
public class parser {
public static void main(String[] args) throws IOException {
XmlMapper mapper = new XmlMapper();
String XML="<?xml version=\"1.0\" encoding=\"UTF-8\"?>\r\n" +
"<open>\r\n" +
" <creds priv=\"write\" type=\"internal\">\r\n" +
" <user>Username1</user>\r\n" +
" <client_token>abcplaudzrbcy37c</client_token>\r\n" +
" <client_secret>0cxDE3LE0000=</client_secret>\r\n" +
" </creds>\r\n" +
" <creds priv=\"read\" type=\"internal\">\r\n" +
" <user>Username1</user>\r\n" +
" <client_token>123plaudzrbcy37c</client_token>\r\n" +
" <client_secret>0cxDE3LE1234=</client_secret>\r\n" +
" </creds>\r\n" +
" <creds priv=\"none\" type=\"internal\">\r\n" +
" <user>Username1</user>\r\n" +
" <client_token>000plaudzrbcy37c</client_token>\r\n" +
" <client_secret>0cxDE3LEabcd=</client_secret>\r\n" +
" </creds>\r\n" +
"</open>";
OpenCredentials openCredentials = mapper.readValue(new StringReader(XML), OpenCredentials.class);
System.out.println(openCredentials);
}
}
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlRootElement;
@JacksonXmlRootElement(localName = "open")
class OpenCredentials {
@JacksonXmlProperty(localName = "creds")
@JacksonXmlElementWrapper(useWrapping = false)
private Credentials[] credentials;
//getters, setters, toString
}
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
class Credentials {
@JacksonXmlProperty(isAttribute = true)
private String priv;
@JacksonXmlProperty(isAttribute = true)
private String type;
@JacksonXmlProperty(localName = "user")
private String user;
@JacksonXmlProperty(localName = "client_token")
private String clientToken;
@JacksonXmlProperty(localName = "client_secret")
private String clientSecret;
//getters, setters, toString
}
Я попробовал приведенный выше код, но получаю сообщение об ошибке,
Исключение в потоке "main" java.lang.NullPointerException по адресу com.fasterxml.jackson.dataformat.xml.deser.FromXmlParser.addVirtualWrapping(FromXmlParser.java:279) по адресу com.fasterxml.jackson.dataformat.xml.deserconrial.ra(WrapperHandlingDeserializer.java:143) в com.fasterxml.jackson.dataformat.xml.deser.WrapperHandlingDeserializer.deserialize(WrapperHandlingDeserializer.java:111) в com.fasterxml.jackson.databind.ObjectMapAj.jj com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3037) в jacksonxml2java.Parser.main(Parser.java:61)