Ответ 1
То, что вы делаете, должно работать. Вот пример:
Модель домена (Foo)
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Foo {
private String bar;
public String getBar() {
return bar;
}
public void setBar(String bar) {
this.bar = bar;
}
}
Demo
import javax.xml.bind.*;
import javax.xml.parsers.*;
import javax.xml.transform.*;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
public class Demo {
public static void main(String[] args) throws Exception {
// Create the JAXBContext
JAXBContext jc = JAXBContext.newInstance(Foo.class);
// Create the Object
Foo foo = new Foo();
foo.setBar("Hello World");
// Create the Document
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document document = db.newDocument();
// Marshal the Object to a Document
Marshaller marshaller = jc.createMarshaller();
marshaller.marshal(foo, document);
// Output the Document
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
DOMSource source = new DOMSource(document);
StreamResult result = new StreamResult(System.out);
t.transform(source, result);
}
}
Выход
<?xml version="1.0" encoding="UTF-8" standalone="no"?><foo><bar>Hello World</bar></foo>