Ответ 1
вот окончательное решение.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Box</title>
<style type="text/css">
#ClickBox {
width:640px;
height:480px;
cursor:pointer;
background:#2f2f2f;
top:50px;
color:#fff;
font:bold 12px Arial;
position: relative;
top: 50px;
left:100px;
}
</style>
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
</head>
<body>
<div id="ClickBox">
<?php foreach($boxes as $box){ ?>
<a href="#" data-toggle="tooltip" data-placement="top" title="<?php echo $box['note']; ?>"> <span style="position:absolute;left:<?php echo $box['position_left']; ?>px;top:<?php echo $box['position_top']; ?>px;background-color:#fff;width:10px;height:10px;"></span> </a>
<?php } ?>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<script type="text/javascript">
$( '#ClickBox' ).click( function(e){
var coordX = e.pageX - $(this).offset().left,
coordY = e.pageY - $(this).offset().top;
var note = window.prompt("Please Enter Note","Your Note Will Comes Here");
var values = {coordX:coordX,coordY:coordY,note:note};
var controller = 'box';
var base_url = '<?php echo site_url(); ?>';
var myurl = base_url + controller + '/add_note/';
$.ajax({
type: "POST",
url: myurl,
data: values,
complete: function (data) {
$('#ClickBox').empty().html(data.responseText);
}
});
});
</script>
</body>
</html>