Обратный порядок дискретной оси у в ggplot2

Ситуация и данные

У меня есть фреймворк df позиций спортсмена в гонке (я уже melted для использования с ggplot2):

df <- structure(list(athlete = c("A", "B", "C", "D", "E", "F", "G",
"H", "I", "J", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", 
"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "A", "B", "C", 
"D", "E", "F", "G", "H", "I", "J", "A", "B", "C", "D", "E", "F", 
"G", "H", "I", "J", "A", "B", "C", "D", "E", "F", "G", "H", "I", 
"J"), distanceRemaining = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 
3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L, 4L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 6L, 6L, 6L, 6L, 
6L, 6L, 6L, 6L, 6L, 6L), .Label = c("1400m", "1200m", "600m", 
"400m", "200m", "FINISH"), class = "factor"), position = c(10, 
6, 7, 8, 2, 1, 3, 5, 9, 4, 9, 8, 7, 6, 4, 3, 1, 5, 10, 2, 8, 
7, 9, 5, 6, 2, 3, 1, 10, 4, 9, 8, 6, 5, 7, 3, 2, 4, 10, 1, 4, 
5, 1, 6, 8, 3, 2, 7, 10, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10)), row.names = c(NA, 
-60L), .Names = c("athlete", "distanceRemaining", "position"), class = "data.frame")

Я рисую данные с помощью

library(ggplot2)
g <- ggplot(df, aes(x=distanceRemaining, y =position, colour=athlete, group = athlete))
g <- g + geom_point()
g <- g + geom_line(size=1.15)
g <- g + scale_y_discrete()
g

Чтобы дать

Вопрос

Как изменить порядок оси y так, чтобы 10 находилось внизу, а 1 - вверху?

Ответы

g <- ggplot(df, aes(x=distanceRemaining, y =position, colour=athlete, group = athlete))
g <- g + geom_point()
g <- g + geom_line(size=1.15)
g <- g +  scale_y_continuous(trans = "reverse", breaks = unique(df$position))
g

require(dplyr)
df <- df %>% mutate(position = factor(position), 
                    position = factor(position, levels = rev(levels(position)))

ggplot(df, aes(x = distanceRemaining, y = reorder(position, desc(position))))

ggplot(df, aes(x = distanceRemaining, y = forcats::fct_rev(factor(position))))