Ответ 1
Вы можете инициализировать объект MultiplePartialViewsResult следующим образом с помощью новых представлений ViewDatastrong > / ViewData.Model. (отлично работает для меня):
return new MultiplePartialViewsResult(
//PartialView("~/Views/RowSumView.cshtml", new List<double>() { 1.0 }),
//PartialView("~/Views/ColumnSumView.cshtml", new List<double>() { 2.0 })
new PartialViewResult() { ViewName = "~/Views/RowSumView.cshtml", ViewData = new ViewDataDictionary() { Model = new List<double>() { 1.0 } } },
new PartialViewResult() { ViewName = "~/Views/ColumnSumView.cshtml", ViewData = new ViewDataDictionary() { Model = new List<double>() { 2.0 } } }
);
Результат пользовательского действия:
public class MultiplePartialViewsResult : ActionResult {
private const string Separator = "-";
private PartialViewResult[] _partialViews;
public MultiplePartialViewsResult(params PartialViewResult[] partialViews) {
_partialViews = partialViews;
}
public override void ExecuteResult(ControllerContext context) {
foreach(var partialView in _partialViews) {
partialView.ExecuteResult(context);
context.HttpContext.Response.Output.Write(Separator);
}
}
}
Контроллер:
public ActionResult Index() {
return View();
}
public ActionResult FakeAction() {
return new MultiplePartialViewsResult(
//PartialView("~/Views/RowSumView.cshtml", new List<double>() { 1.0 }),
//PartialView("~/Views/ColumnSumView.cshtml", new List<double>() { 2.0 })
new PartialViewResult() { ViewName = "~/Views/RowSumView.cshtml", ViewData = new ViewDataDictionary() { Model = new List<double>() { 1.0 } } },
new PartialViewResult() { ViewName = "~/Views/ColumnSumView.cshtml", ViewData = new ViewDataDictionary() { Model = new List<double>() { 2.0 } } }
);
}
Просмотров:
Индекс
@Html.Action("FakeAction")
ColumnSumView.cshtml/RowSumView.cshtml:
@model List<double>
<ul>
@foreach(double item in Model) {
<li>@item</li>
}
</ul>