Ответ 1

Взгляните на следующий пример

CREATE TABLE #Table (
        ID INT,
        ColumnName VARCHAR(250),
        Value VARCHAR(250)
)

INSERT INTO #Table SELECT 1,'name','Peter' 
INSERT INTO #Table SELECT 1,'phone','12345678' 
INSERT INTO #Table SELECT 1,'email','[email protected]' 
INSERT INTO #Table SELECT 2,'name','John' 
INSERT INTO #Table SELECT 2,'phone','87654321' 
INSERT INTO #Table SELECT 2,'email','[email protected]' 
INSERT INTO #Table SELECT 3,'name','Sarah' 
INSERT INTO #Table SELECT 3,'phone','55667788' 
INSERT INTO #Table SELECT 3,'email','[email protected]' 

---I assumed your tablename as TESTTABLE--- 
DECLARE @cols NVARCHAR(2000) 
DECLARE @query NVARCHAR(4000) 

SELECT  @cols = STUFF(( SELECT DISTINCT TOP 100 PERCENT 
                                '],[' + t.ColumnName 
                        FROM    #Table AS t 
                        --ORDER BY '],[' + t.ID 
                        FOR XML PATH('') 
                      ), 1, 2, '') + ']' 

SELECT  @cols

SET @query = N'SELECT ID,'+ @cols +' FROM 
(SELECT t1.ID,t1.ColumnName , t1.Value FROM #Table AS t1) p 
PIVOT (MAX([Value]) FOR ColumnName IN ( '+ @cols +' )) 
AS pvt;' 

EXECUTE(@query)

DROP TABLE #Table

Ответ 2

попробуйте следующее:

SQL Server 2005 +

 ;with 
        cte_name  as(select * from <table> where ColumnName='name'),
        cte_phone as(select * from <table> where ColumnName='phone'),
        cte_email as(select * from <table> where ColumnName='email')
  select n.ItemID,n.Value [Name],p.Value [Phone],e.Value [Email] 
  from  cte_name n
  join  cte_phone p
  on    n.ItemID=p.ItemID
  join  cte_email e
  on    n.ItemID=e.ItemID

SQL Fiddle Demo

Ответ 3

Вам не нужен динамический стержень, потому что это будет другая таблица. Просто сделайте что-нибудь вроде этого:

name    phone   email
---------------------------------
Peter            
        123456
                 [email protected]

Отметьте скрипт SQL

SELECT DISTINCT u.ItemID, n.Value as 'name', p.Value as 'phone', e.Value as 'email'
FROM UserData u
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'name') n ON n.ItemID = u.ItemID
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'phone') p ON p.ItemID = u.ItemID
INNER JOIN(
SELECT ItemID, Value 
FROM UserData WHERE ColumnName = 'email') e ON e.ItemID = u.ItemID

Ответ 4

Вот запрос, который я использую для моего контактного списка:)

SELECT *
FROM
    (
    SELECT Contact_Id AS CT
          , [Age]
          , [Sex]
          , [State]
          , [Country]
          , [Keyword]
          , [Married]
          , [Kids]
          , [Car]
     FROM
         (SELECT c.PropertyName
               , c.ValueString
               , c.Contact_Id
          FROM
              ContactProfiles c) AS ctp
         PIVOT (max(ctp.ValueString) FOR PropertyName IN ([Age], [Sex], [State], [Country], [Keyword], [Married], [Kids], [Car])) AS PivotTable
         ) AS pvt

WHERE
    pvt.[Age] > 18
    AND (pvt.[State] = 'CA' OR pvt.[State] = 'NY')
    AND pvt.[Sex] = 'F'
    --*AND pvt.[Keyword] LIKE '%B;%'
    AND pvt.[Married] = 'True'
    AND pvt.[Kids] > 0

Ответ 5

Вы пробовали это:

SELECT ItemID, name, phone, email
FROM
(SELECT [ItemID] ,[ColumnName] ,[Value] FROM Item) Item
PIVOT (MAX(Value) FOR ColumnName IN (name, phone, email) ) as pvt