Ретрансляция запроса в asp.net(пересылка запроса)

Ответ 1

Собственно, что-то вроде этого хорошо работало

HttpRequest original = context.Request;
HttpWebRequest newRequest = (HttpWebRequest)WebRequest.Create(newUrl);

newRequest .ContentType = original.ContentType;
newRequest .Method = original.HttpMethod;
newRequest .UserAgent = original.UserAgent;

byte[] originalStream = ReadToByteArray(original.InputStream, 1024);

Stream reqStream = newRequest .GetRequestStream();
reqStream.Write(originalStream, 0, originalStream.Length);
reqStream.Close();


newRequest .GetResponse();

edit: метод ReadToByteArray просто делает байтовый массив из потока

Ответ 2

У меня есть метод расширения на HttpResponseBase, чтобы скопировать входящий запрос на исходящий запрос.

Использование:

    var externalRequest = (HttpWebRequest)WebRequest.Create("http://stackoverflow.com");
    this.Request.CopyTo(externalRequest);
    var externalResponse = (HttpWebResponse)externalRequest.GetResponse();

Источник:

/// <summary>
/// Copies all headers and content (except the URL) from an incoming to an outgoing
/// request.
/// </summary>
/// <param name="source">The request to copy from</param>
/// <param name="destination">The request to copy to</param>
public static void CopyTo(this HttpRequestBase source, HttpWebRequest destination)
{
    destination.Method = source.HttpMethod;

    // Copy unrestricted headers (including cookies, if any)
    foreach (var headerKey in source.Headers.AllKeys)
    {
        switch (headerKey)
        {
            case "Connection":
            case "Content-Length":
            case "Date":
            case "Expect":
            case "Host":
            case "If-Modified-Since":
            case "Range":
            case "Transfer-Encoding":
            case "Proxy-Connection":
                // Let IIS handle these
                break;

            case "Accept":
            case "Content-Type":
            case "Referer":
            case "User-Agent":
                // Restricted - copied below
                break;

            default:
                destination.Headers[headerKey] = source.Headers[headerKey];
                break;
        }
    }

    // Copy restricted headers
    if (source.AcceptTypes.Any())
    {
        destination.Accept = string.Join(",", source.AcceptTypes);
    }
    destination.ContentType = source.ContentType;
    destination.Referer = source.UrlReferrer.AbsoluteUri;
    destination.UserAgent = source.UserAgent;

    // Copy content (if content body is allowed)
    if (source.HttpMethod != "GET"
        && source.HttpMethod != "HEAD"
        && source.ContentLength > 0)
    {
        var destinationStream = destination.GetRequestStream();
        source.InputStream.CopyTo(destinationStream);
        destinationStream.Close();
    }
}

Ответ 3

Вот хороший код реле в VB.NET с использованием MVC.

GLOBAL.ASAX.VB

Public Class MvcApplication
    Inherits System.Web.HttpApplication

    Shared Sub RegisterRoutes(ByVal routes As RouteCollection)
        routes.MapRoute("Default", "{*s}", New With {.controller = "Home", .action = "Index"})
    End Sub

    Sub Application_Start()
        RegisterRoutes(RouteTable.Routes)
    End Sub
End Class

HomeController.vb

Option Explicit On
Option Strict On

Imports System.Net

<HandleError()> _
Public Class HomeController
    Inherits System.Web.Mvc.Controller

    Function Index(ByVal s As String) As ActionResult
        Server.ScriptTimeout = 60 * 60
        If Request.QueryString.ToString <> "" Then s = s + "?" + Request.QueryString.ToString
        Dim req As HttpWebRequest = CType(WebRequest.Create("http://stackoverflow.com/" + s), HttpWebRequest)
        req.AllowAutoRedirect = False
        req.Method = Request.HttpMethod
        req.Accept = Request.Headers("Accept")
        req.Referer = Request.Headers("Referer")
        req.UserAgent = Request.UserAgent
        For Each h In Request.Headers.AllKeys
            If Not (New String() {"Connection", "Accept", "Host", "User-Agent", "Referer"}).Contains(h) Then
                req.Headers.Add(h, Request.Headers(h))
            End If
        Next
        If Request.HttpMethod <> "GET" Then
            Using st = req.GetRequestStream
                StreamCopy(Request.InputStream, st)
            End Using
        End If
        Dim resp As WebResponse = Nothing
        Try
            Try
                resp = req.GetResponse()
            Catch ex As WebException
                resp = ex.Response
            End Try

            If resp IsNot Nothing Then
                Response.StatusCode = CType(resp, HttpWebResponse).StatusCode
                For Each h In resp.Headers.AllKeys
                    If Not (New String() {"Content-Type"}).Contains(h) Then
                        Response.AddHeader(h, resp.Headers(h))
                    End If
                Next
                Response.ContentType = resp.ContentType

                Using st = resp.GetResponseStream
                    StreamCopy(st, Response.OutputStream)
                End Using
            End If
        Finally
            If resp IsNot Nothing Then resp.Close()
        End Try
        Return Nothing
    End Function
    Sub StreamCopy(ByVal input As IO.Stream, ByVal output As IO.Stream)
        Dim buf(0 To 16383) As Byte
        Using br = New IO.BinaryReader(input)
            Using bw = New IO.BinaryWriter(output)
                Do
                    Dim rb = br.Read(buf, 0, buf.Length)
                    If rb = 0 Then Exit Do
                    bw.Write(buf, 0, rb)
                Loop
            End Using
        End Using
    End Sub
End Class

Ответ 4

HttpContext включает свойство Request, которое, в свою очередь, содержит коллекцию Headers. Это должна быть вся необходимая информация.

Ответ 5

возможно что-то вроде:

HttpWebRequest request = (HttpWebRequest)WebRequest.Create("www.testing.test");
request.Headers = (WebHeaderCollection)Request.Headers;

Затем вызовите ответ get

HttpWebResponse response  = (HttpWebResponse)request.GetResponse();

Это будет иметь те же заголовки HTTP, что и исходный запрос.